h^2=30^2+60^2

Solution for h^2=30^2+60^2 equation:

h^2=30^2+60^2

We move all terms to the left:

h^2-(30^2+60^2)=0

We add all the numbers together, and all the variables

h^2-4500=0

a = 1; b = 0; c = -4500;
Δ = b2-4ac
Δ = 02-4·1·(-4500)
Δ = 18000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18000}=\sqrt{3600*5}=\sqrt{3600}*\sqrt{5}=60\sqrt{5}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{5}}{2*1}=\frac{0-60\sqrt{5}}{2}
=-\frac{60\sqrt{5}}{2}
=-30\sqrt{5}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{5}}{2*1}=\frac{0+60\sqrt{5}}{2}
=\frac{60\sqrt{5}}{2}
=30\sqrt{5}
$